Math, asked by DHARAMAHIR4034, 10 months ago

Solve of find the greatest four digit number which when divided by 20,30,35 and 45 leaves reminder 12 in each case

Answers

Answered by azit89mukhia
3

Answer:

The greatest four digit number = 9999

Step 1: find the L.C.M. of 20, 30, 35 and 45

L.C.M.=1260

Step 2:  divide 9999 by 1260. we get the remainder 1179

Step 3: subtract 1179 from 9999

9999-1179=8820

Step 4: 8820 is exactly divisible by 20, 30, 35 and 45

Step 5: Add 12 and 8820

8820+12=8832

Therefore the required number=8832

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