solve on a square + b square + c square minus A square + b square + c square
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a^2 + b^2 + c^2 - (a^2 + b^2 + c^2)
a^2 + b^2 + c^2 - a^2 - b^2 -c^2
= 0
a^2 + b^2 + c^2 - a^2 - b^2 -c^2
= 0
SakshaM725:
I typed correct or incorrect
Answered by
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a2 +b2 +c2-[a2+b2+c2] =a2+b2+c2-a2-b2-c2
=0
=0
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