Question

solve on copy pleasee...



Find the value of k, for which one root of the quadratic equation kx^2-14x 8=0 is 2

Answer 1

Answer:-

k = 5.


Step by Step Explanation



Given quadratic equation

$kx {}^{2} - 14x + 8 = 0$

It is given that one root of the quadratic equation is 2

Put x = 2

$= > k(2) {}^{2} - 14(2) + 8 = 0 \\ \\ = > 4k - 28 + 8 = 0 \\ \\ = > 4k - 20 = 0 \\ \\ = > 4k = 20 \\ \\ = > k = \frac{20}{4} \\ \\ = > k = 5.$


Hope it helps!

Answer 2

$\underline{\large\bf{\mathfrak{Hello!}}}$

$According \: to \: the \: question \: one \\ root \: of \: quadratic \: equation \: is \: 2. \\ \\ x = 2 \\ \\ So, \\ \\ = > k {x}^{2} - 14x + 8 = 0 \\ = > k( {2)}^{2} - 14(2) + 8 = 0 \\ = > 4k - 28 + 8 = 0 \\ = > 4k - 20 = 0 \\ = > 4k = 20 \\ = > k = \frac{20}{4} \\ = > k = 5$

$\boxed{k = 5}$

$\bf{\mathfrak{Hope \: this \: helps...:)}}$