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PR divides parallogram in two equal triangle
∆ SPR and ∆ PQR
So Area of ∆ SPR + ∆ PQR = area of parallogram
Area of Triangle ∆ SPR ;- 1/2 * base * height
= 1/2 * 24*6 = 72 cm^2
Area of Triangle ∆ PQR ;- ;- 1/2 * base * height
= 1/2 * 24*6 = 72 cm^2
area of parallogram ;- 72+72;- 144cm^2
thanks me Later ❤️
∆ SPR and ∆ PQR
So Area of ∆ SPR + ∆ PQR = area of parallogram
Area of Triangle ∆ SPR ;- 1/2 * base * height
= 1/2 * 24*6 = 72 cm^2
Area of Triangle ∆ PQR ;- ;- 1/2 * base * height
= 1/2 * 24*6 = 72 cm^2
area of parallogram ;- 72+72;- 144cm^2
thanks me Later ❤️
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