Math, asked by kaushikeebhatt, 1 year ago

solve ot plz urgent

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Answered by Anonymous

$\frac{4 + 2 \sqrt{3}} {2 - \sqrt{3} } \\ on \: rationalizing \: denominator \\ = \frac{ \: 4 + 2 \sqrt{3}}{ 2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } \\ = \frac{8 + 4 \sqrt{3 } + 4 \sqrt{3} + 6 }{ {2}^{2} - { \sqrt{3} }^{2} } \\ = \frac{14 + 8 \sqrt{3} }{4 - 3} \\ = \frac{14 + 8 \sqrt{3} }{1} \\ = 14 + 8 \sqrt{3}$
THEN a = 14 AND b = 8√3
HOPE IT HELPS YOU

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