Question

solve(p-1) (p³+2p²+p) ​

Answer 1

Answer:

answer is p⁴-p³-p²-p

Step-by-step explanation:

(p-1)(p³+2p²+p)

p⁴+2p³+p²-p³-2p²-p

p⁴-p³-p²-p

hope it helps you

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Answer 2

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• Solve for p :

$\:\:\:\:\:\:\:\:\:\: (p-1)(p^3 + 2p^2 + p) = 0$

★ANSWER★

• $\boxed{\bf{ p=0,1,-1,-1}}$

⍟ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴ⍟

Let us factorize the expression and solve it as follows:

$\:\:\:\:\: (p-1)(p^3 + 2p + p) = 0$

$\to (p-1)p(p^2 + 2p + 1) = 0$

$\to p(p-1)(p^2 + 2p.1 + 1^2) = 0$

$\to p(p-1)(p + 1)^2 = 0$

$\to p=0\:or\:p-1=0$

$\:\:\:\:\: or\:p + 1= 0\:or\:p+1 = 0$

$\to p=0,1,-1,-1$