Solve: p^2-6p-40+14q-q^2
Answers
Answered by
13
Answer:p^2-6p-40+14q-q^2
=p^2-6p+3^2-3^2-40+14q-q^2
=p^2-2.p.3+3^2-9-40+14q-q^2 [3^3 and -3^2 is added]
=(p-3)^2-49+14q-q^2 [a^2-2ab+b^2=(a-b)^2 is used]
=(p-3)^2-(49-14q+q^2)
=(p-3)^2-(7^2-2.7.q+q^2)
=(p-3)^2-(7-q)^2
=(p-3+7-q)(p-3-7+q) [a^2-b^2=(a+b)(a-b) is used]
=(p+4-q)(p-10+q)
Step-by-step explanation:
Answered by
0
Answer:
p2-6p-40+
Step-by-step explanation:
Similar questions