Solve - p^3-(p+1)^3
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-p^3-p^3-1 -3p^2-3p=0
2p^3+3p^2+3p+1
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Answer:
Step-by-step explanation:
Using the identity, a^3 - b^3 = (a^2 + b^2 + 2ab)
p^3 - (p + 1)^3
= {p - (p + 1)} { (p)^2 + (p + 1)^2 + p*(p + 1) }
= ( -1 ) ( p^2 + p^2 + 1 + 2p + p^2 + p )
= ( -1 ) ( 3p^2 + 3p + 1 )
= -3p^2 - 3p - 1
Hope it helps :)
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