Math, asked by nejac4784, 1 year ago

Solve p square q square plus (p square minus q square) x minus q square is equal to zero

Answers

Answered by vishalpatil12345
227

p2x2+(p2-q2)x-q2=0


p2x2 + p2x - q2x - q2 = 0


p2x ( x + 1 ) - q2 ( x + 1 ) = 0


( x + 1 ) = 0 or ( p2x - q 2 ) = 0


therefore x = -1 or x = q2 / p2

Answered by mysticd
99

Answer:

 x = -1 \: Or \: x = \frac{q^{2}}{p^{2}}

Explanation:

Given quadratic equation:

x²+(-q²)x-q²=0

Splitting the middle term, we get

=> x²+p²x-x-q²=0

=> x(x+1)-(x+1)=0

=> (x+1)(x-)=0

=> x+1 = 0 Or x- = 0

\implies x = -1 \: Or \: p^{2}x = q^{2}

\implies x = -1 \: Or \: x = \frac{q^{2}}{p^{2}}

Therefore,

 x = -1 \: Or \: x = \frac{q^{2}}{p^{2}}

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