Solve p square q square plus (p square minus q square) x minus q square is equal to zero
Answers
Answered by
227
p2x2+(p2-q2)x-q2=0
p2x2 + p2x - q2x - q2 = 0
p2x ( x + 1 ) - q2 ( x + 1 ) = 0
( x + 1 ) = 0 or ( p2x - q 2 ) = 0
therefore x = -1 or x = q2 / p2
Answered by
99
Answer:
Explanation:
Given quadratic equation:
p²x²+(p²-q²)x-q²=0
Splitting the middle term, we get
=> p²x²+p²x-q²x-q²=0
=> p²x(x+1)-q²(x+1)=0
=> (x+1)(p²x-q²)=0
=> x+1 = 0 Or p²x-q² = 0
Therefore,
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