Question

Solve p² - 5p+6=0 differncial equation
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Answer 1

Answer:

Solve p² - 5p+6=0 differncial equation

Answer 2

Answer:P^2 - 5P + 6 =0

P^2 - 3P - 2P + 6 =0

P(P-3)-2(P-3)=0

(P-3)(P-2)=0

p-3=0. p-2=0

p=3. p=2

(OR)

p2-5p+6=0

We add all the numbers together, and all the variables

p^2-5p+6=0

a = 1; b = -5; c = +6;

Δ = b2-4ac

Δ = -52-4·1·6

Δ = 1

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

p1=−b−Δ√2ap2=−b+Δ√2a

Δ−−√=1√=1

p1=−b−Δ√2a=−(−5)−12∗1=42=2

p2=−b+Δ√2a=−(−5)+12∗1=62=3