Question

Solve : p2 – 6p + 36 = 0.

Answer 1

The value of p are $3+3\sqrt{3}i\ and \ 3-3\sqrt{3}i$

Step-by-step explanation:

Given: $p^2-6p+36=0$

This is quadratic equation and solve for p

Using quadratic formula to find p

Quadratic formula:-

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

where a is coefficient of p², b is coefficient of p and c is constant term

a = 1

b = -6

c = 36

Substitute the value into formula

$p=\dfrac{-(-6)\pm\sqrt{(-6)^2-4(1)(36)}}{2(1)}$

$p=\dfrac{6\pm\sqrt{-108}}{2}$

$p=3\pm3\sqrt{3}i$        $[\because \sqrt{-1}=i]$

$p=3+3\sqrt{3}i,p=3-3\sqrt{3}i$

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