Question

Solve P²+P=6 please solve this problem

Answer 1

Answer:

Step-by-step explanation:

P^2+P=6

P^2+P-6=0

P^2+3P-2P-6=0

P(P+3)-2(P+3)=0

(P-2)(P+3)=0

P-2=0

P=2

Also

P+3=0

P=-3

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Answer 2

${p}^{2} - p - 6 = 0$
${p}^{2} - 3p + 2p - 6 = 0$
p(p-3)+2(p-3)=0
:.(p-3) (p+2)
:.p-3=0 or p+2=0

p=3 or p=(-2)



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