Question

solve:p²-p(e^x+e^-x)+1=0​

Answer 1

Step-by-step explanation:

The given equation is p2 – p(ex + e–x) + 1 = 0 ...(i) dy = ex dx Integrating, we get y = ex + c1 ...(iv) From Eq. (iii), we get, (dy/dx).ex - 1 = 0 exdy = dx dy = e-xdx Integrating, we get y = c2 – e–x Hence, the general solution of Eq. (i) is (x – e–x – c)(y – e–x – c) = 0.Read more on Sarthaks.com - https://www.sarthaks.com/563813/solve-p-2-p-e-x-e-x-1-0?show=563823#a563823