Question

Solve : p² + q² = n² ​

Answer 1

(p suqur -q square) -(p suqur -q square)

=p suqur -q square - p suqur +q square

=0

Answer 2

$(p+q+n)(p+q-n)-2pq=0$

Step-by-step explanation:

We have,

$p^2+q^2=n^2$

To find, $p^2+q^2=n^2=?$

∴ $p^2+q^2=n^2$

Using algebraic identity,

$(a+b)^{2}=a^{2}+b^{2}+2ab$

⇒ $a^{2}+b^{2}=(a+b)^{2}-2ab$

⇒ $(p+q)^{2}-2pq=n^2$

⇒ $(p+q)^{2}-n^2-2pq=0$

⇒ $[(p+q)^{2}-n^2]-2pq=0$

Using algebraic identity,

$a^{2}-b^{2}=(a+b)(a-b)$

⇒ $[(p+q)+n][(p+q)-n]-2pq=0$

⇒ $(p+q+n)(p+q-n)-2pq=0$

∴ $(p+q+n)(p+q-n)-2pq=0$