Question

solve pair of equations by cross multiplication method​

Answer 1

• Equations are :
• Eq(1) => 4x + 7y = 16xy
• Eq(2) => 10x + 3y = 11xy
• now multiplying eq(1) by 5 and eq(2) by 2 , we get
• 20x + 35y = 80xy
• 20x + 6y = 22xy
• now subtract both equation ,
• 20x - 20x + 35y - 6y = 80xy - 22xy
• 29y = 58xy
• cancel y
• 58x = 29
• x = 29/58 = 29 ÷ 58 = ½
• Value of x = ½
• then , substitute value of x in eq1 , we get
• 4(½) + 7y = 16(½)y
• 2 + 7y = 8y
• 8y - 7y = 2
• y = 2
• Value of y = 2

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