Question

solve pair of linear equations: x/a+y/b = a+b ; x/a^2 + y/b^2 =2​

Answer 1

Answer:

/a+y/b-(a+b) = 0……………..(1).

x/a^2+y/b^2–2 = 0…………………(2).

x/{-2/b+(a+b)/b^2} = y/{-(a+b)/a^2+2/a} = 1/{1/ab^2–1/a^2b}.

x/{(a-b)/b^2} = y/{(a-b)/a^2} = 1/{(a-b)/a^2.b^2}.

x.b^2 = y.a^2 = a^2.b^2.

x= a^2.b^2/b^2 =a^2.

y =a^2.b^2/a^2 = b^2.

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Answer 2

Answer:

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