Question

solve pairs of simuntaneous equation
43x + 31y = 98
31x + 43y = 50​

Answer 1

Answer:

Multiply the equation 47x+31y=63 by 31 and equation 31x+47y=15 by 47 to make the coefficients of x

equal. Then we get the equations:

1457x+961y=1953.........(1)

1457x+2209y=705.........(2)

Subtract Equation (1) from Equation (2) to eliminate x, because the coefficients of x are the same. So, we get

(1457x−1457x)+(2209y−961y)=32−27

i.e. 1248y=−1248

i.e. y=−1

Substituting this value of y in the equation 47x+31y=63, we get

47x−31=63

i.e. 47x=94

i.e. x=2

Hence, the solution of the equations is x=2,y=−1.

Answer 2

Answer:

above is the answer ^^^and the answer is right

Step-by-step explanation:

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