Question

solve please ✌ ..........
​

Answer 1

OLAAA ✌

Answer:

23and9

Step-by-step explanation:

Let the two numbers be x and y respectively.

Given that ;

The difference between the two numbers is 14.

⇒ x - y = 14.... (i)

Difference between their squares is 448.

⇒ x² - y² = 448

⇒ (x + y)(x - y) = 448

⇒ (x + y) * 14 = 448

⇒ x + y = \sf \dfrac{448}{14}

14

448

⇒ x + y = 32 .....(ii)

_______________________

On adding equation (i) and (ii) -

⇒ x - y + x + y = 14 + 32

⇒ 2x = 46

⇒ x = \sf \dfrac{46}{2}

2

46

⇒ x = 23

Substituting the value of x in (i)

⇒ x - y = 14

⇒ 23 - y = 14

⇒ y = 23 - 14

⇒ y = 9

_______________________

Hence, the two required numbers are 23 and 9.

$<marquee behaviour= "alternate">$"FOLLOW "\:ME \: PLEASE $<marquee direction="down">$

✌✌✌❤❤❤☺ ☺ ☺

☺

Answer 2

Answer:

23 and 9

Step-by-step explanation:

let two nos be x and y

acc to eqn x-y=14

${x}^{2} - {y}^{2} = 448$

${(14 + y )}^{2} - {y}^{2} = 448$

$196 + {y}^{2} + 28y - {y}^{2} = 448$

cancel out both the y^2

28y=448-196

28y=252

y=9

w.k.t x-y=14

subs y=9 in above eqn

x-9=14

x=14+9

therefore x=23.....