CBSE BOARD X, asked by nensnbne, 1 year ago

solve please
................

.......​

Attachments:

Answers

Answered by Anonymous
3

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

#TOGETHER WE GO FAR✔✔

Attachments:
Answered by Anonymous
3

Answer:

=(1+cosA/sinA-1/sinA).(1+sinA/cosA+1/cosA)

=(sinA+cosA-1)×(cosA+sinA+1)/sinA.cosA)

=[(sinA+cosA)^2-(1)^2]/sinA.cosA.

=(sin^2A+cos^2A+2.sinA.cosA-1)/sinA.cosA.

=( 1+2.sinA.cosA -1)/sinA.cosA.

= 2.sinA.cosA/sinA.cosA

= 2

Similar questions