Math, asked by ranjhna809, 8 months ago

Solve please...........​

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Answered by Anonymous
56

Question-

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</u><u>\</u><u>s</u><u>f</u><u>\</u><u>g</u><u>r</u><u>e</u><u>e</u><u>n</u><u>{</u><u>( {3x}^{2}  -  \frac{1}{5} x +  \frac{7}{3} ) + ( -  \frac{1}{4}  {x}^{2}  +  \frac{1}{3} x - \frac{1}{6} ) + ( - 2 {x}^{2}   -  \frac{1}{2} x + 5)</u><u>}</u><u>

Step-by-step explanation-

Required sum

 \sf {= ( {3x}^{2}  -  \frac{1}{5} x +  \frac{7}{3} ) + ( -  \frac{1}{4}  {x}^{2}  +  \frac{1}{3} x - \frac{1}{6} ) + ( - 2 {x}^{2}   -  \frac{1}{2} x + 5)}

Now, collecting all the like terms.

\sf { = 3 {x}^{2} -  \frac{1}{4} {x}^{2}  - 2 {x}^{2}  -  \frac{1}{5} x -  \frac{1}{2} x + ( \frac{7}{3} -  \frac{1}{6}   + 5)}

Then, adding the like terms.

\sf { = (3 -  \frac{1}{4}  - 2) {x}^{2}  + (  - \frac{1 }{5}  +  \frac{1}{3}  -  \frac{1}{2} )x + ( \frac{7}{3}  -  \frac{1}{6}  + 5)}

\sf { = ( \frac{12 - 1 - 8}{4} ) {x}^{2}  + ( \frac{ - 6 + 10 - 15}{30} )x + ( \frac{14 - 1 + 30}{6} )}

\sf { =  \frac{3}{4}  {x}^{2}  -  \frac{11}{30} x +  \frac{43}{6}  \:  \:  \: ans...}

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Additionally-

Before learning algebraic expression you have to know what is constants and variables.

  • Constant - A symbol having fixed numerical value is called a constant. Ex - 7, 9, -3 etc.

  • Variable - A symbol which takes various numeric values is known as a variable. Ex - x, y, z , b etc.

  • Algebraic expression - A combination of constants and variables connected by some or all of the four fundamental operations +, - , × , ÷ is called an algebraic expression.
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