Question

Solve please...... ........

Answer 1

Given principal = 3000, R = 10%, n = 2 years.

We know that A = P(1 + r/100)^n

                            = 3000(1 + 10/100)^2

                            = 3000(1 + 1/10)^2

                            = 3000(11/10)^2

                            = 3000 * 11/10 * 11/10

                            = 3630.


We know that CI = A - P

                            = 3630 - 3000

                            = 630.


Therefore the CI = 630.

Hope this helps!

Answer 2

Hello friend.

_____________________________


Given::

Principal (P) = 3000 Rupees.

Rate of Interest (R) = 10% per annum

Period (N) = 2 years.

We have to find,

Compound Interest = ???

We know that,

Compound Interest= P(1+R/100)^N - P

By putting the given values we get,

Compound Interest = 3000(1+10/100)^2-3000

Compound Interest = 3000(1+ 1/10^2 - 3000

Compound Interest = 3000(11/10)^2-3000

Compound Interest = 3000 x 121/100 - 3000

Compound Interest = 30 x 121 - 3000

Compound Interest = 3630 - 3000

Compound Interest = 630



Thanks....

:)