Question

solve please...

4. ABCD is a parallelogram. The diago-
nals AC and BD intersect each other
at O. Prove that ar (AAOD) = ar (ABOC).
[Hint : Congruent figures have equal
area]

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Answer 1

Answer:

In triangle AOD and triangle BOC,

AD = BC (opposite sides of

parrallelogram are equal)

angle ADO = angle OBC (alternate angles are

equal)

angle DAO = angle OCB (alternate angles are

equal)

Therefore triangle AOD is congruent to triangle BOC.

Therefore ar(AOD) = ar(BOC)

Answer 2

Answer:

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