Math, asked by adarshqwe, 1 year ago

solve please ...........​

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Answered by mishratanisha7492
0

according to the identity,

(a-b)^3 = a^3 - b^3 -3ab(a-b)

we will distribute the question as

(998)^3 = (1000-2)^3

now,

(1000-2)^3 = (1000)^3 - 2^3 -

3×1000×2(1000-2)

= 1,000,000,000 - 8 - 6000(1000-2)

= 1,000,000,000 - 8 - 6,000,000 + 12000

= 994,011,992

hence,

(998)^3 = 994,011,992

hope it helps.....

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