solve please ...........
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according to the identity,
(a-b)^3 = a^3 - b^3 -3ab(a-b)
we will distribute the question as
(998)^3 = (1000-2)^3
now,
(1000-2)^3 = (1000)^3 - 2^3 -
3×1000×2(1000-2)
= 1,000,000,000 - 8 - 6000(1000-2)
= 1,000,000,000 - 8 - 6,000,000 + 12000
= 994,011,992
hence,
(998)^3 = 994,011,992
hope it helps.....
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