Question

solve please and answer​ quick SSC

Answer 1

Answer:

$sec \theta = \frac{197}{28}$

Step-by-step explanation:

$sec {}^{2} \theta - {tan}^{2} \theta = 1 \\ \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ \\ sec \theta - tan \theta = \frac{1}{sec \theta + tan \theta} \\ \\ given \\ \\ sec \theta + tan \theta = 14 \: \: \: \: \: \: \: eq1 \\ \\ sec \theta - tan \theta = \frac{1}{14} \: \: \: \: \: \: \: eq2 \\ \\ eq1 + eq2 \\ \\ 2sec \theta = 14 + \frac{1}{14} \\ \\ 2sec \theta = \frac{197}{14} \\ \\ sec \theta = \frac{197}{28}$

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Answer 2

Answer:

$\begin{lgathered}sec \theta = \frac{197}{28} \\ \\\end{lgathered}$

Step-by-step explanation:

$\begin{lgathered}sec {}^{2} \theta - {tan}^{2} \theta = 1 \\ \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ \\ sec \theta - tan \theta = \frac{1}{sec \theta + tan \theta} \\ \\ given \\ \\ sec \theta + tan \theta = 14 \: \: \: \: \: \: \: eq1 \\ \\ sec \theta - tan \theta = \frac{1}{14} \: \: \: \: \: \: \: eq2 \\ \\ eq1 + eq2 \\ \\ 2sec \theta = 14 + \frac{1}{14} \\ \\ 2sec \theta = \frac{197}{14} \\ \\ sec \theta = \frac{197}{28} \\ \\\end{lgathered}$