solve please cos 2 theta= sin 30° × tan 60°
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Given
=> cos2θ = sin30°tan30°
=> 2cos²θ - 1 = 1/2 × 1/√3
=> 2cos²θ = 1/2√3 + 1
=> cos²θ = (1 + 2√3)/2
=> cosθ = [(1 + 2√3)/2]^½
Hope it may Help you.✌️
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