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x² - 11x + 29 = 1 (x-4) (x-7)= 0
x² - 11x + 28 = 0
X1 - 4
x2 = 7
6x² + x 2 = 0 (3x + 2)(2x − 1) = 0
(3x + 2)(2x − 1) = 0
x6 = 6
x3 = T 2|3
X4 = 1/2
Case 3: a = -1 and b is even.
x² - 11x + 29 = - 1
x² 11x + 30 = 0 (x - 5)(x - 6) = 0
X5 = 5
X6 = 6
The possible answers are therefore
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