Question

solve please give solution in comment

Answer 1

total initial volume=44.8dm3
2H2 +O2 =2H2O
at ideal gas condition 1 mole of O2 react with 2 moles of H2 giving rise 2 moles of H2O with final volume of 22.4dm3
so difference is 22.4dm3

Answer 2

it is direct see and answer question.
22.4L means 1 mole of any gas at STP.
hence no of moles given are:
1 mol hydrogen and 1mol oxygen gas
.
these react to form 1 mol of water(H2 is limiting here).
hence,
initial volume of container = 44.8,
moles of O2 left : 1/2 moles = 11.2L volume.
moles of H2 left = 0,
moles of water formed=1mol= 22.4L
hence final volume of container = 11.2+22.4=33.6L
=> change in volume of container= 11.2L .