Math, asked by ashoksolanke1717, 10 months ago

solve please help me by giving the answer step by step​

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Answered by Anonymous
1

ab+bc+ca=0

ab+bc = -ca

Or ab+ca= -bc

Or bc+ca = -ab

Now

1/(a^2 -bc) + 1/(b^2 -ca) + 1/(c^2 -ab)

= 1/(a^2 +ab+ca) +1/(b^2 +ab+bc) +1/(c^2 +bc+ca)

= 1/(a+b+c) * (1/a + 1/b + 1/c)

= 1/(a+b+c) * (bc + ca + ab)/abc

= (ab+bc+ca)/(a+b+c) abc

= (a+b+c) abc/(a+b+c) abc

=0

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