Question

Solve please I have exam

Answer 1

which question do you want me to solve

Answer 2

Area of the trapezium = h/2 (a + b) where a and b are the parallel sides and h is the perpendicualr distance between the parallel sides.
Area of the trapezium ABCD = AB/2 (AD + BC)
24.5 = (AB/2) (10 + 4)
49 = AB (14)
AB = 3.5 cm

Radius of the quadrant of the circle = AB = 3.5 cm
Area of the quadrant of the circle = (1/4) (πr2) = (1/4) (22/7 x 3.5 x 3.5) = 9.625 cm2

Area of the shaded region = Area of the trapezium - Area of the quadrant of the circle
                                      = 24.5 - 9.625
                                      = 14.875 cm2