Question

❤️Solve please ❤️


If 8 ∙ 2x = 5(y+8), then when y = -8, x

Answer 1

when y=-8
rhs =5(-8+8)
=0
therefore
lhs=8.2x
so for lhs =rhs to satisfy
x=0

Answer 2

Given,

$8*2^{x} = 5^{y + 8} \\ \\ \text{Putting y = -8} \\ \\ 2^{3}*2^{x} = 5^{-8+8} \\ \\ 2^{x+3} = 5^{0} \\ \\ 2^{x+3} = 1 \\ \\ x+3 = \log_2 1 \\ \\ x+ 3 = \log_2 2^{0} \\ \\ x+3 = 0*\log_2 2 \\ \\ x+3 = 0*1 \\ \\ x + 3 = 0 \\ \\ x = -3 \ \textbf{Ans.}$