Question

Solve please .....

If possible solve all.....✋✋✋

Or u people solve only 16 question..⛎⛎⛎⛎⛎⛎⛎

Answer 1

Q.16
angleFAC = angleFAD
angleDAE = angleEAB

=> angleCAD = 2 * angleFAD. ......(i)
angleDAB = 2 * angleDAE. ......(ii)

Adding (i) & (ii), we get
angleCAD + angleDAB = 2(FAD+DAE)
therefore, angleCAB = 2 * 90° = 180°
So, CAB is a straight line.

Therefore, B, A and C are collinear.






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Answer 2

Q.13. let x=5a, y=6a,z=9a

x+y+z=180°(forming straight angle )
5a+6a+9a=180°
20a=180°
a=180°/20=9
x=5×9=45°,y=6×9=54°, z=9×9=81°

Q14. LET first angle =3x, second angle=7x
3x+7x=180°(forming straight angle)
10x=180°
x=180°/10=18
first angle =3×18=54°
second angle=7×18=126°

Q15. Draw a perpendicular line QS
now , by the law of reflection angle of incidence = angle if reflection
so , angle SQP=angle SQR
Angle SQP+SQR=Angle PQR
angle SQP+angle SQP=100°(Since angle SQP=Angle SQR)
2angleSQP=100°
Angle SQP=100°/2=50°
Angle SQP=50°=Angle SQR
now , angle SQP+Angle PQA=90°(since QS is drawn perpendicular to AB)
50°+angle PQA=90°
Angle PQA=90°-50°=40°
NOW, angle PQA+Angle PQR+Angle RQB=180°(forming straight angle)
40°+100° +angle RQB=180°
140°+Angle RQB=180°
Angle RQB=180°-140°=40°

Q16. AE is perpendicular to AF
SO,angle FAE=90°
angle CAF=Angle DAF(AF bisects angle DAC)
Angle EAB=Angle DAE(AE bisects DAB)
angle CAF+Angle EAB= angle DAF+Angle DAE
angle CAF+angle EAB=angle FAE=90°
now , angle CAF +angle EAB+angleFAE
=90°+90°=180=angle CAB
its forming a straight angle and a straight angle forms a straight line so , A,B,C lines on a straight line so , A,B,C are collinear.

hope it helped you