Question

solve please its urgent
solve

Answer 1

g
$\\ \: let \: natural \: no \: be \: x {}^{2} \: \\ so \: according \: to \: question \\ x {}^{ 2} = 3 \times \sqrt{x { \: }^{2} } + 4 = 0\\ x {}^{2 } - 3x - 4 = 0\\ x {}^{2 } - 4x + x \: - 4 = 0 \\ x(x - 4) + 1(x - 4) = 0 \\ ( x+ 1)( x- 4) = 0$
either

X = -1

or

x = 4

for natural no.

either

x2= -1× -1
x2 =1
x2=1


or.

x2 = 4×4

x2=. 16