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3
Hey Mate
your answer is --
Let, A and B are two vectors .
Given, A = B ......(1)
Let, B is the resultant
Let, angle between them is @
So,
√A^2+B^2+2ABcos@ = B
=> √B^2+B^2+2B^2cos@ = B ( from 1)
=> 2B^2 + 2B^2cos@ = B^2
=> 2B^2(1+cos@) = B^2
=> 1 + cos@ = 1/2
=> cos @ = (1/2)-1
=> cos@ = -1/2
=> cos@ = cos120° [ since, cos120°=-1/2]
=> @ = 120°
Hence, angle between two vectors is 120°
【 Hope it helps you 】
your answer is --
Let, A and B are two vectors .
Given, A = B ......(1)
Let, B is the resultant
Let, angle between them is @
So,
√A^2+B^2+2ABcos@ = B
=> √B^2+B^2+2B^2cos@ = B ( from 1)
=> 2B^2 + 2B^2cos@ = B^2
=> 2B^2(1+cos@) = B^2
=> 1 + cos@ = 1/2
=> cos @ = (1/2)-1
=> cos@ = -1/2
=> cos@ = cos120° [ since, cos120°=-1/2]
=> @ = 120°
Hence, angle between two vectors is 120°
【 Hope it helps you 】
Answered by
2
Heya!!Here is your answer friend ⤵⤵
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