Accountancy, asked by harvinder52, 1 year ago

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Answered by xoSHOAIBxo
0

If you are talking about an n-sided convex polygon, then its number of diagonals are given by nC2 - n; and if

nC2 - n = 44 (given), then

½ n (n - 1) - n = 44

n^2 - n - 2 n = 88

n^2 - 3 n - 88 = 0

Solving the quadratic, we have

n^2 - 11 n + 8 n - 88 = 0

(n - 11) (n + 8) = 0

Since, n = -8 is not applicable, hence the polygon in question must have 11 number of sides to it.


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Answered by TħeRøмαи
52

Answer:

If you are talking about an n-sided convex polygon, then its number of diagonals are given by nC2 - n; and if

nC2 - n = 44 (given), then

½ n (n - 1) - n = 44

n^2 - n - 2 n = 88

n^2 - 3 n - 88 = 0

Solving the quadratic, we have

n^2 - 11 n + 8 n - 88 = 0

(n - 11) (n + 8) = 0

Since, n = -8 is not applicable, hence the polygon in question must have 11 number of sides to it.

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