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Let distance be d
Speed (1) = 20km/h
Time taken = distance / speed
= d/20
Speed (2) = 30km/h
Time = Distance/time
= d/30
Average speed = total distance /total time
=( d+d) /{(d/20)+(d/30)}
= 2d / (d/12)
=24d/ d
= 24
So, the average speed of the car was 24km/h
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Let distance be d
Speed (1) = 20km/h
Time taken = distance / speed
= d/20
Speed (2) = 30km/h
Time = Distance/time
= d/30
Average speed = total distance /total time
=( d+d) /{(d/20)+(d/30)}
= 2d / (d/12)
=24d/ d
= 24
So, the average speed of the car was 24km/h
✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️
Answered by
1
Speed = Distance / Time taken
Distance = Speed × Time taken
Time taken = Distance / Speed
time taken while going to college = t
time taken when return to home = T
( while going to college) t= S/20 hr
( return to home ) T = S/ 30 hr
Total time taken by Akhil Ta = t + T
===> ( S/20 + S/30 )
===> 1/10 ( S/2 + S/3)
===> 1/10 ( 2S+3S/6)
===> 1/10 ( 5S/6)
===> 1/2 ( S/6)
===> S/12
Total distance = S( going ) + S( return) = 2S
....(route of going and return is same)
Average speed = Total distance dravelled / time taken
===> 2S/ S/12
===> 2×12S/S
===> 24 km/ hr
hence average speed is 24 km / hr of akhil' s car
Distance = Speed × Time taken
Time taken = Distance / Speed
time taken while going to college = t
time taken when return to home = T
( while going to college) t= S/20 hr
( return to home ) T = S/ 30 hr
Total time taken by Akhil Ta = t + T
===> ( S/20 + S/30 )
===> 1/10 ( S/2 + S/3)
===> 1/10 ( 2S+3S/6)
===> 1/10 ( 5S/6)
===> 1/2 ( S/6)
===> S/12
Total distance = S( going ) + S( return) = 2S
....(route of going and return is same)
Average speed = Total distance dravelled / time taken
===> 2S/ S/12
===> 2×12S/S
===> 24 km/ hr
hence average speed is 24 km / hr of akhil' s car
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