Question

solve please this question properly​

Answer 1

Answer:

hope the answer will help you

Answer 2

Explanation:

2ohm and 4ohm are in series

so Rnet=R1+R2=4+2=6ohm

10ohm and 7 ohm are in series

so Rnet=7+10=17ohm

now we have 3 resistirs in parallel

which are 6ohm,6ohm,17ohm

6ohm and 6ohm ate in parallel

so Rnet=R1R2/R1+R2

Rnet=6×6/6+6=36/12=3ohm

3ohm and 17 ohm are in parallel

so Rnet=17×3/17+3=51/20=2.55ohm

you will never get 5ohm as the answer