Question

solve please

urgent...

Answer 1

Answer:

Hey Mate...

Step-by-step explanation:

Son = 12 years old and Mother = 42 years old

Define x:

Let x be the age of the son 6 years ago

Mother = x²

Find the current age now:

Son = x + 6

Mother = x²  + 6

Find their age 3 years later:

Son = x + 6 + 3 = x + 9

Mother =  x²  + 6 + 3 =  x²  + 9

Solve x:

x²  + 9 = 3(x + 9)

x²  + 9 = 3x + 27

x²  - 3x - 18 = 0

(x - 6)(x + 3) = 0

x = 6 or x = -3 (rejected)

Find their current age:

Son = x + 6 = 6 + 6 = 12 years old

Mother =  x²  + 6 = (6)² + 6 = 42 years old

Answer: Son = 12 years old and Mother = 42 years old

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Answer 2

Let the sons present age be x

then

Age of son 16 year before = x-6

Age of mother 6 year before=(x-6)^

After 3 years

son age will be = x+3

And

Mother age will be = 3 (x+3)---1

Now

Mother age will also =(x-6)^+9 ( with the respect of past)

then

(x-6)^+9= 3 (x+3)

x^-12x+36+9=3x + 9

x^-12x -3x +36=0

x^-15x+36=0

x^-12x -3x +36=0

x (x-12)-3 (x-12)=0

(x-3)(x-12)=0

x=12. (3 is neglected)

Son age=12

and

mother age= 3 ( x+3)

=3 (12+3)

=3×15

45