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Answer:
23and9
Step-by-step explanation:
Let the two numbers be x and y respectively.
Given that ;
The difference between the two numbers is 14.
⇒ x - y = 14.... (i)
Difference between their squares is 448.
⇒ x² - y² = 448
⇒ (x + y)(x - y) = 448
⇒ (x + y) * 14 = 448
⇒ x + y = \sf \dfrac{448}{14}
14
448
⇒ x + y = 32 .....(ii)
_______________________
On adding equation (i) and (ii) -
⇒ x - y + x + y = 14 + 32
⇒ 2x = 46
⇒ x = \sf \dfrac{46}{2}
2
46
⇒ x = 23
Substituting the value of x in (i)
⇒ x - y = 14
⇒ 23 - y = 14
⇒ y = 23 - 14
⇒ y = 9
_______________________
Hence, the two required numbers are 23 and 9.
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Hii its tom85
let two number ne x and y
according to question
=>x+ y = 14--------(1
=>x^2 - y^2 = 448
=>x - y = 448/14
=>x - y= 32________(2
from ------(1 and ---------(2 on adding we get
=>2x = 46
=>x = 23
now putting the value of x in ------(1 we get
=>23 + y = 14
=>y = - 9
________/\_________☹️
hope it may helps you