Math, asked by pheliu, 11 months ago

solve please urgent need ​

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Answered by DeviIQueen
2

OLAAA ✌

Answer:

23and9

Step-by-step explanation:

Let the two numbers be x and y respectively.

Given that ;

The difference between the two numbers is 14.

⇒ x - y = 14.... (i)

Difference between their squares is 448.

⇒ x² - y² = 448

⇒ (x + y)(x - y) = 448

⇒ (x + y) * 14 = 448

⇒ x + y = \sf \dfrac{448}{14}

14

448

⇒ x + y = 32 .....(ii)

_______________________

On adding equation (i) and (ii) -

⇒ x - y + x + y = 14 + 32

⇒ 2x = 46

⇒ x = \sf \dfrac{46}{2}

2

46

⇒ x = 23

Substituting the value of x in (i)

⇒ x - y = 14

⇒ 23 - y = 14

⇒ y = 23 - 14

⇒ y = 9

_______________________

Hence, the two required numbers are 23 and 9.

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Answered by Anonymous
3

Hii its tom85

let two number ne x and y

according to question

=>x+ y = 14--------(1

=>x^2 - y^2 = 448

=>x - y = 448/14

=>x - y= 32________(2

from ------(1 and ---------(2 on adding we get

=>2x = 46

=>x = 23

now putting the value of x in ------(1 we get

=>23 + y = 14

=>y = - 9

________/\_________☹️

hope it may helps you

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