Math, asked by kaminigarg8410044, 2 months ago

Solve please very fast​

Attachments:

Answers

Answered by akshitasaxena2709
0

Answer:

required no. = n(HCF(12,18,40))

HCF(12,18,40) = 360

required no.= 27*360 =9720

Answered by TigerMan28
0

Answer:

9720

Step-by-step explanation:

LCM of 12,18,40 and 45.

12 = 2^2 × 3

18 = 2 × 3^2

40 = 2^3 × 5

45 = 3^2 × 5

So, LCM = 2^3 × 3^2 × 5

= 8 × 9 × 5

= 360

As, the greatest 4 digit number is 9999. Dividing 9999 by 360,

We get 27 se the quotient. Now multiplying 360 by 27 gives us our answer as 9720.

Similar questions