Question

solve pleaseeeeeeeeeeeee very fast

Answer 1

Answer:

this is the answer. ()()()((00 snap

Answer 2

Answer:

441 is the right answer

thanks

Step-by-step explanation:

let EFGH and PQRS

PQ=90m

PS=3m

AREA OF PQRS PATH =PQ×PS

=90×3

= 270

EF=3m

FG=60m

AREA OF EFGH=EF×FG

=3×60

=180

AREA OF KLMN IS COMMON TO THE BOTH THE PATH

KL=3

LM=3

AREA OF KLMN=KL×LM

=KL×LM

=3×3

= 9

SHADED AREA = AREA OF PQRS +EFGH- AREA OF KLMN.

=270+180-9

=450-9

=441