Question

Solve
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Answer 1

Since it is in $\frac{0}{0}$ form,L Hospital rule can be used.

Differentiating numerator and denominator, we get

lim x->0 $\frac{4sin4x}{5sin5x}$

Now,again it is in $\frac{0}{0}$ form, so again differentiate it.

We get,

lim x->0 $\frac{16cos4x}{25cos5x}$

Now ,substitute 0 for x.

We get $\frac{16cos0}{25cos0}$

= $\frac{16}{25}$

Answer 2

Answer:

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