Math, asked by SupriyaRastogi76, 10 months ago

Solve plss,Factorise​

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Answers

Answered by siddhartharao77
4

Step-by-step explanation:

Given Equation is 4x² - 4a²x + (a⁴ - b⁴) = 0

⇒ 4x² - 2a²x - 2a²x + (a⁴ - b⁴) = 0

⇒ 4x² - 2a²x - 2a²x - 2b²x + 2b²x + (a⁴ - b⁴) = 0

⇒ 4x² - 2a²x - 2b²x - 2a²x + 2b²x + (a⁴ - b⁴) = 0

⇒ 4x² - 2(a² + b²)x - 2(a² - b²)x + (a² + b²)(a² - b²) = 0

⇒ 2x[2x - (a² + b²)] - (a² + b²)[2x - (a² + b²)] = 0

⇒ (2x - (a² + b²))(2x - (a² - b²)) = 0

(i)

2x - (a² + b²) = 0

⇒ 2x = a² + b²

x = (a² + b²)/2

(ii)

2x - (a² - b²) = 0

⇒ 2x = (a² - b²)

x = (a² - b²)/2

Hope it helps!

Answered by sujal78678
0

Answer:

correct answer is x= (a2+b2)/2

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