Question

solve plz .......
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Answer 1

$\huge{Answer}$

${3}^{ x + 2} + {3}^{ - x = 10}$

${3}^{x} \times {3}^{2} + \frac{1}{ {3}^{x} } = 10$

${3}^{x} \times 9 + \frac{1}{ {3}^{2} } = 10$

Here

$t = {3}^{2}$

$t \times 9 + \frac{1}{t} = 10$

$t = 1$

$t = \frac{1}{9}$

${3}^{x} = 1$

$3 = \frac{1}{9}$

$x = 0$

$x = - 2$