Question

solve plz...............​

Answer 1

$= \frac{ {2}^{x + 1} + {2}^{x} }{ {2}^{x - 1} - {2}^{x} } \\ = \frac{ {2}^{x} {2}^{1} + {2}^{x} }{{2}^{x} {2}^{ - 1} - {2}^{x}} \\ = \frac{ {2}^{x}(2 + 1) }{{2}^{x}( {2}^{ - 1} - 1)} \\ = \frac{3}{ (\frac{1}{2} - 1) } \\ = \frac{3}{ \frac{1 - 2}{2} } \\ = \frac{3}{ - \frac{ 1}{2} } \\ = \frac{3}{1} \times - \frac{2}{1} \\ = - 6$