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Answer:
13 numbers are divisible by 7
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Given:
a ( first term ) = 14 ( lowest two digit number which is divisible by 7 )
d ( common difference ) = 7
an ( last term ) = 98 ( highest two digit number which is divisible by 7 )
To Find:
n ( total two digit numbers which are divisible by 7 )
Formula:
an = a + ( n - 1 )d
Solution:
By putting the respected values, we get
98 = 14 + ( n - 1 )7
or, 98 - 14 = ( n - 1 )7
or, 84 / 7 = n - 1
or, 12 + 1 = n
or, 13 = n
Answer:
Total two digit numbers which are divisible by 7 are 13.
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