Question

solve plz ..............​

Answer 1

refractive index =sin i/sin r

sin 30/sin 45

(1/2)/(1/√2)

√2/2

1.414/2

0.707

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Answer 2

Answer:

Angle of incidence(i) = 90°-30° = 60°

Angle of refraction(r) = 45°

Therefore;

Refractive index of liquid with respect to air = sin i / sin r

= sin 60° / sin 45°

= (√3/2) / (1/√2)

= √6/2 (Ans)

Explanation:

First of all , 30° is not the angle of incidence. From the definition of angle of incidence - it is the angle between the incident ray and the normal, therefore; angle of incidence(i) = 90° - 30° = 60°. Now , angle of refraction(r) is 45° (angle between refracted ray and the normal). Now , you have to use the formula sin i /sin r for the refractive index of liquid with respect to air that's how you will get the answer.............