Math, asked by dhruv2928, 1 year ago

solve plz plz plz plz ​

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Answers

Answered by superjunior
1

hlww....

since,

 {1}^{3}  +  {2}^{3}  +  {3}^{3}.... +  {20}^{3}  \\   =  (\frac{20 \times 21}{2} )sq \\  =  {210}^{2} \\   = 44100


dhruv2928: tq
superjunior: :-)
superjunior: my pleasure to help u !!
Answered by generalRd
2

Question

1+2+3+4+5.......+20= 210

1^3 + 2^3 + 3^3.......+ 20^3 = ?

ANSWER

Here the following sequence can be solved by a very special formula which is=>

1^3 + 2^3 + n^3= \dfrac{n(n+1)(n+1)}{2}

By using this formula we can find the value of this expression.

So, we get =>

1^3+2^3...............+20^3

=>20\times\dfrac{20+1}{2}}^2

=> \dfrac{(20)(21)}{2}}^2

=> {10\times21}^2

=> {210}^2

=>44100.

Hence the value of given expression is 44100.

Remember

1^3 + 2^3 + n^3= n\times\dfrac{(n+1)(n+1)}{2}

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