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(a) highest: 48 ohm
(b) lowest: 2 ohm
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Answer:
(a)24Ω is the lowest total resistance.
(b) 2 Ω is the lowest total resistance.
Explanation:
Answer: Given resistances R1 =4 Ω, R2=8 Ω, R3=12Ω, and R4=24Ω.
(a) If these coils are connected in series, then the equivalent resistance will
be the highest, as R=R1+R2+R3+R4
∴ R=4+8+12+24 = 24Ω
(b) If these coils are connected in parallel, then the equivalent resistance will be the lowest, given by
1/R=1/R1+1/R2+1/R3+1/R4
1/R=1/4+1/8+1/12+1/24
1/R=6+3+2+1
1/R=12/24=12
⇒R=2 Ω
∴ 2 Ω is the lowest total resistance.
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