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=cos35°/sin55°+tan27°tan63°÷sin30°-3tan²60°.
{cos35°=cos(90-55)=sin55°
tan63°=tan(90-27)=cot27°
tan.cot=1
sin30°=1/2
tan60°=√3}
on substituting the values.
=sin55°/sin55°+tan27°cot27°÷1/2-3(√3)²
=1+1÷1/2-3(3)
=1+2-9
=3-9
= -6.
Hope the answer helps you.
TQ.
All the very best..
{cos35°=cos(90-55)=sin55°
tan63°=tan(90-27)=cot27°
tan.cot=1
sin30°=1/2
tan60°=√3}
on substituting the values.
=sin55°/sin55°+tan27°cot27°÷1/2-3(√3)²
=1+1÷1/2-3(3)
=1+2-9
=3-9
= -6.
Hope the answer helps you.
TQ.
All the very best..
Akshaymas:
say me the question correctly.
Answered by
0
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