Question

solve plzz
5
$( \sqrt[5]{3} ) {4x + 7 = ( \sqrt[11]{27} ) {2x + 7}^{?}$
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Answer 1

Answer:

x = 2

Step-by-step explanation:

${( \sqrt[5]{3} }^{4x + 7} = {( \sqrt[11]{27}) }^{2x + 7} \\ {( {3}^{ \frac{1}{5} } )}^{4x + 7} = {( {27}^{ \frac{1}{11} } )}^{2x + 7} \\ {3}^{ \frac{4x + 7}{5} } = {( {3}^{ \frac{3}{11} } )}^{ 2x + 7 } \\ {3}^{ \frac{4x + 7}{5} } = {3}^{ \frac{6x + 21}{11} } \\ \\ base \: are \: same \: power \: is \: to \: be \: equated \\ \frac{4x + 7}{5} = \frac{6x + 21}{11} \\ 11(4x + 7) = 5(6x + 21) \\ 44x + 77 = 30x + 105 \\ 44x - 30x = 105 - 77 \\ 14x = 28 \\ x = \frac{28}{14} \\ x = 2$

hope you get your answer